(4x-3)-(x^2+2x)=0

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Solution for (4x-3)-(x^2+2x)=0 equation:


Simplifying
(4x + -3) + -1(x2 + 2x) = 0

Reorder the terms:
(-3 + 4x) + -1(x2 + 2x) = 0

Remove parenthesis around (-3 + 4x)
-3 + 4x + -1(x2 + 2x) = 0

Reorder the terms:
-3 + 4x + -1(2x + x2) = 0
-3 + 4x + (2x * -1 + x2 * -1) = 0
-3 + 4x + (-2x + -1x2) = 0

Combine like terms: 4x + -2x = 2x
-3 + 2x + -1x2 = 0

Solving
-3 + 2x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
3 + -2x + x2 = 0

Move the constant term to the right:

Add '-3' to each side of the equation.
3 + -2x + -3 + x2 = 0 + -3

Reorder the terms:
3 + -3 + -2x + x2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2x + x2 = 0 + -3
-2x + x2 = 0 + -3

Combine like terms: 0 + -3 = -3
-2x + x2 = -3

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -3 + 1

Reorder the terms:
1 + -2x + x2 = -3 + 1

Combine like terms: -3 + 1 = -2
1 + -2x + x2 = -2

Factor a perfect square on the left side:
(x + -1)(x + -1) = -2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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